48=(2h)^2

Solution for 48=(2h)^2 equation:

48=(2h)^2

We move all terms to the left:

48-((2h)^2)=0

determiningTheFunctionDomain
-2h^2+48=0

a = -2; b = 0; c = +48;
Δ = b2-4ac
Δ = 02-4·(-2)·48
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{6}}{2*-2}=\frac{0-8\sqrt{6}}{-4}
=-\frac{8\sqrt{6}}{-4}
=-\frac{2\sqrt{6}}{-1}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{6}}{2*-2}=\frac{0+8\sqrt{6}}{-4}
=\frac{8\sqrt{6}}{-4}
=\frac{2\sqrt{6}}{-1}
$